ANSWER: about 6,000,000,000,000,000,000,000,000,000, or six octillion particles (depending on the size of the room).
WORKING OUT:
First, let’s work out what we mean by ‘average’ sized. Perhaps if we think of my office, or your classroom, how big is this? Perhaps 8 metres wide, 10 metres long, 3 metres high? – Let’s use this as our size. The volume of the room is therfore 8 x 10 x 3 = 240 cubic metres (m^3) – which, if the classroom is empty, is all air.
In chemistry, we learn that one ‘mole’ of particles takes up 24 cubic decimetres (dm^3) when it is a gas (at normal temperature and pressure)
There are 1000 dm^3 in 1 m^3, so our room has 240 x 1,000 = 240,000 dm^3 of air in it.
Therefore, it was 240,000 / 24 = 10,000 moles of air in it.
A ‘mole’ is a large number of particles – the number is known as Avogradro’s constant, which is approxmiately 600,000,000,000,000,000,000,000 (6 with 23 zeroes, or 6 x 10^23). There are 6 x 10^23 particles in one mole of gas.
Therefore, in 10,000 moles of air there will be 10,000 x 6 x 10^23 = 6 x 10^27 particles.
Avogadro’s constant and the amount of space a mole of gas takes up are fixed – so this answer is really dependent on how big your room is. You may have noticed I deliberately picked a room with easy dimensions to work with!
I notice Keith and I worked out our answer at the same time – and that I have forgotten precisely how much space a mole of gas takes! Oh well, I was close enough for an estimate 🙂 – my room was a bit larger, too, but you’ll see that either way you are talking several octillion particles!
Comments
Aaron commented on :
I notice Keith and I worked out our answer at the same time – and that I have forgotten precisely how much space a mole of gas takes! Oh well, I was close enough for an estimate 🙂 – my room was a bit larger, too, but you’ll see that either way you are talking several octillion particles!